Kenny Omega To Defend AAA Mega Championship At Triplemania

Kenny Omega vs Laredo Kid AAA Triplemania

AAA Lucha Libre has been making announcements for their 28th Triplemania event and while we have no show date we do have the news that Kenny Omega will defend the AAA Mega Championship against Laredo Kid.  This will mark Omega’s fourth title defense but only the second one to take place on a AAA event.  His last came against Dragon Lee at Triplemania Regia in late 2019.  The other defenses have taken place on All Elite Wrestling (AEW) Event.

Laredo Kid is a good choice for Omega’s opponent, not only is Kid quite talented but he has history with Omega both in AEW and AAA.  In 2019 Kid teamed with the Lucha Bros. to take on The Elite (Omega, Nick Jackson & Matt Jackson) in two matches, the first was a defeat on AEW soil, the second was a win for the Lucha team at last year’s Triplemania event.  Now Kid gets Kenny Omega for the Mega Championship, the richest prize in all of AAA.

Also announced for Triplemania was Pagano vs Chessman in a hair vs hair match that is sure to dive into Lucha extrema territory as neither man is afraid to embrace hardcore wrestling.  We also do not yet have a date for Triplemania but they hope to run the event in December, the show will also have 7 matches but only two have been announced so far.

Stay tuned to the Last Word on Pro Wrestling for more on this and other stories from around the world of wrestling, as they develop. You can always count on LWOPW to be on top of the major news in the wrestling world, as well as to provide you with analysis, previews, videos, interviews, and editorials on the wrestling world.  Subscribe to AAA on Twitch to see more from Mexico’s top company.

Looking to talk wrestling, pro football, or any number of sports? Head on over to the LWOS Boards to engage in conversation with fellow fans!

Leave a Reply

Your email address will not be published. Required fields are marked *

This site uses Akismet to reduce spam. Learn how your comment data is processed.